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lim(x,y)→(0,0)x^2y/x^3+y^3,怎么解求大神指点

lim(x,y)→(0,0)x^2y/x^3+y^3,怎么解求大神指点沿路径y=x^(3/2),趋向于无穷,limxy/(x^3+y^2)=lim1/2x^(1/2)->∞因此极限不存在。这种

limx^2y/(x^3-y^3)的极限,(x,y)趋向于(0,0)当x=0而y趋向0时函数趋向0,当x=-y趋向0时,表达式可改写为-y^3/(-2y^3)=1/2趋向1/2。说明

(x^2y^2)/(x^3+y^3)的在x,y都趋于0的重极限证明x,y趋于0时,x^2y/(x^4+y^3)的极限不存在 2017-11-07 lim x^2y^2/x^2y^2+(x-y)

证明lim(x,y)->(0,0)(x2y/x3-y3)不存在(x,y)->(0,0)可以令y=x,算极限然后在令y=-x,算极限带入算出来极限不相等,违背极限

(x^2y^2)/(x^3+y^3)的在x,y都趋于0的重极限在两个特别的方向上极限为无穷大,其余方向上为0。所以,本题的极限不存在。具体解答如下:

极限lim-x^2y/x^3-y^3,x趋于0,y趋于1.x趋于0,y趋于1

求极限lim(x,y)→(0,0) x^2y^2/(x^2+y^2)^(3/2)回答:x=rcost, y=rsint; 原式=r^4*(sin2t)^2/4/r^3=r(sin2t)/4->0

证明x,y趋于0时,x^2y/(x^4+y^3)的极限不存在证明lim(x,y)→(0,0) (x+2y)/(2x-y)极限不存在 2017-09-26 证明极限x^2*y^2/x^2*y^

lim(x,y)->(0,0){(x^2y^2- 2|x|-6|y|)/(|x|回答:原式=

问:(x,y)趋近于(0,0)时,(x^2+y^2)^(x^2y^2)的极限怎么(1)对函数f(x,y)=(x^2+y^2)^(x^2y^2)取对数后有|x^2y^2ln(x^2+y^2)|≤[

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